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The maximum number of molecules is present in

The maximum no of molecules is present in

This Free PDF Notes contains the maximum number of molecules is present in (a)15L of H​​​​​​2 gas at STP, (b) 5L of of N​​​​​​2 gas at STP, (c) 0.5g of H​​​​​​2 gas and (d) 10g of O​​​​​​2 gas for upcoming government exams. In addition, the maximum no of molecules is present in ? in terms of moles, we can say that whichever gas has maximum number of molar quantity will have maximum number of molecules in it.

• The maximum number of molecules is present in
• (a)15L of H​​​​​​2 gas at STP
• (b) 5L of of N​​​​​​2 gas at STP
• (c) 0.5g of H​​​​​​2 gas and
• (d) 10g of O​​​​​​2 gas
• Correct answer is (a)15L of H​​​​​​2 gas at STP

To find the the maximum number of molecules is present in we can convert all the options into one unit (in terms of moles) because we know that whichever gas has maximum number of molar quantity will definitely have maximum number of molecules in it. so-

• (i) Number of moles in 15 L of H2 gas at STP. = (15 L / 22.4 L) = 0.67 moles
• (ii) Number of moles in 5 L of N2 gas at STP. = (5 L / 22.4 L) = 0.22 moles
• (iii) Number of moles in 0.5 g of ​H2 gas = (0.5 g / 2 g mol-1) = 0.25 moles
• (iv) Number of moles in 10 g of O2 gas = (10 g / 32 g mol-1) = 0.312 moles

Maximum no of molecules is present in

The distinguishable feathers of the gases possess the indistinguishable number of the molecules in them if they’ve the identical number of moles which is directly commensurable or limpid to the Avogadro number. So we easily find the number of moles of the substance by mass divided by molar mass. Number of Moles is equal to the mass of the substance is divided by the molar mass of that substance. We know that One mole is equal to 22.4L. So first we will find the the maximum number of molecules is present in 15 L of H2 gas at STP

Which of the following has maximum number of molecules

Which of the following has maximum number of molecules – (a)15L of H​​​​​​2 gas at STP, (b) 5L of of N​​​​​​2 gas at STP, (c) 0.5g of H​​​​​​2 gas and (d) 10g of O​​​​​​2 gas. Now lets find out the number of molecules present in 15 L of H2 gas at STP. So 15 L of H2 gas means that given volume of hydrogen gas is 15L. Similarly we can find for others as well.

We know that Moles = Given Volume/22.4L

So number of moles present in 15 Hydrogen gas is = 15L/22.4L = 0.669 Moles. We know that number of moles is directly proportional to the number of molecules. So total number of molecules in 15L hydrogen gas is 0.669

• (ii) Number of moles in 5 L of N2 gas at STP. = (5 L / 22.4 L) = 0.22 moles
• (iii) Number of moles in 0.5 g of ​H2 gas = (0.5 g / 2 g mol-1) = 0.25 moles
• (iv) Number of moles in 10 g of O2 gas = (10 g / 32 g mol-1) = 0.312 moles

which of the following contains maximum number of molecules

(a)15L of H​​​​​​2 gas at STP

which has maximum number of molecules

(a)15L of H​​​​​​2 gas at STP

which of the following has maximum number of molecules

(a)15L of H​​​​​​2 gas at STP

the number of water molecules is maximum in

18 moles of water