Cotx cot2x-cot2x cot3x-cot3x cotx=1 Formula
Prove that Cot X Cot 2x – Cot 2x Cot 3x – Cot 3x Cot X = 1 : In Trigonometry, we can easily find the relation between the angles and perpendicular, hypotenuse, base all sides of a triangle. The main concept behind Cotx cot2x cot2x cot3x cot3x cotx 1 is trigonometric Functions of Sum and Difference of Two Angles of sides of a triangle.
Prove that cot x. cot 2x – cot 2x. cot3x – cot x. cot3x = 1
To prove this trigonometric formula Cotx cot2x cot2x cot3x cot3x cotx 1, we have to use the trigonometric function of (cot (A+B) = ((cot A. cot B -1)/ (cot A + cot B)).
- Consider LHS of cot x. cot 2x – cot 2x. cot3x – cot x. cot3x = 1
- cot x. cot 2x – cot 2x. cot3x – cot x. cot3x
- cot x. cot 2x- cot 3x . (cot 2x+cot x) ——-> equation (1)
- 2x + x = 3x take both sides, cot so it will become cot(x + 2x) = cot3x
Using the Trigonometric formula, cot (A+B) = ((cot A. cot B -1)/ (cot A + cot B), We have, cot (2x+x) = ((cot 2x. cot x – 1) / (cot 2x + cot x)) Now we can put this value of cot(2x + x) or value of cot3x into equation 1.
- So now equation (1) becomes
- cot x. cot 2x- cot2x.cotx–1cot2x+cotxcot2x.cotx–1cot2x+cotx . (cot 2x+cot x)
- = cot x. cot 2x- cot 2x. cot x – 1
- = 1 Which is equal to RHS
So LHS = RHS Hence proved. cot x. cot 2x – cot 2x. cot3x – cot x. cot3x = 1
How do you solve 1/cotx formula
Prove that 1 / cot x = tan x. We know that trigonometric ratio cot θ is equal to adjacent / opposite and cot a = cos a /sin a. Using these trigonometric ratios we can easily prove 1 / cot x = tan x formula.
- 1 / cot x can be expressed in terms of sin and cos as 1 / cot x = 1/ (cos x / sin x)
- 1 / cot x = sin x / cos x
We know that trigonometric ratio sin x / cos x is equal to tan x
So 1 / cot x = (sin x / cos x) and we know that sinx/cosx is equal to tanx. After substituting the values we will get 1 / cot x = tan x.
So 1 / cot x = tan x Hence proved. Please follow this link of Explanation of Mathematics formula – Click
cot x = cos x divide by sin x and 1/cotx is equal to tanx
Tanx = 1/cotx
1/cotx = tanx can be simplified in easy manner. Please go through this post
Cotx = 1/Tanx
The integral of cot x is ∫ cot x dx = ln |sin x| + C.
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