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Algebra identities and notes in Hindi, algebraic formulas

This Free PDF Notes Contains Basic Algebra notes pdf in hindi and Basic algebraic formulas For Upcoming Exams. You can easily download this list of Important Formulas in Algebra in Hindi from given link below . You can also get algebra identities, algebraic equations, Algebra Handwritten Notes, Maths tricks, mathematics book pdf for competitive exams.

Hello Dear Examtrix.com followers, In this post we are going to share an important PDF on Algebra notes pdf in hindi and Basic algebraic formulas, which is very useful for each and every competitive exam in India. At this platform we share Maths Algebra Handwritten notes pdf in Hindi-English and Mathematics Class notes Free Pdf Study material for Competitive exams.

Today, we are sharing SSC CGL free notes, free upsc ias material. This PDF Notes (Algebra identities and notes in Hindi, algebraic formulas) is important for various exams like UPSC, IAS, RAS, UPPSC, MPPSC, BPSC, SSC CGL, CHSL, CPO, IBPS PO, SBI PO, Railway, RRB NTPC, ASM, Group D, State PSC, Sub inspector, Patwari exam, LDC Exam, Revenue office Exam.

In this PDF following topics are covered :
  1. Algebra Formulas, algebra formulas in hindi, algebra by 25 trick
  2. Algebra Handwritten Notes in Hindi
  3. Important algebra Results, algebra for competitive exams pdf,
  4. Algebra Notes in Hindi, algebra mathematics in hindi, Download Algebra PDF in Hindi

This PDF is  prepared by Examtrix Team. All credit goes to them.

PDF Size : 2 Mb

No of pages in this PDF : 11

To Download Free Study Material : Algebra Handwritten Notes Pdf in Hindi

Click Here to Download this PDF : Algebra Formulas pdf

Here is a list of Algebraic formulas –
a2 – b2 = (a – b)(a + b)
(a+b)2 = a2 + 2ab + b2
a2 + b2 = (a – b)2 + 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc
(a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(a – b)3 = a3 – 3a2b + 3ab2 – b3
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4)
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4)
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)
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